Python program for display all leap years from 1900 to 2101

In this tutorial we will write a Python program for display all leap years from 1900 to 2101 . Before reading further we recommend to read about following articles –

• Python For Loop
• Range function in Python
• If-Else Statement in Python

What is leap year ?

Generally a year has 365 days but a leap year has 366 days . A year will be said a leap year if the year fulfills the below conditions-

• The year should be divisible by 400
• The year should be divisible by 4 but not by 100

Example :

• 2000 is a leap year as it is divisible by 400
• 2004 is a leap year as it is divisible by 4
• 2100 is not a leap year because it is divisible by 4 and 100 .

Python program to check if a year is leap year or not

Steps:

• First we will check if the year is divisible by 400 or not . If the year is divisible by 400 we will print the year is a leap year
• Then we will check if the year is divisible by 4 and not divisible by 100 . If the year fulfills this condition then we will print the year is a leap year
• otherwise we will print the year is not a leap year

year=2100
# checking if the year divisible by 400 or not
if year%400==0:
    print(year,"is a leap year")
# checking if the year divisible by 4 and not by 100    
elif year%4==0 and year%100!=0:
    print(year,"is a leap year")    
else:
    print(year,"is not a leap year")   

2100 is not a leap year

As 2100 is divisible by 4 and by 100 so it is not a leap year .

Python program for display all leap years from 1900 to 2101

Steps:

• First we will initialize start and end variable with the start year and end year .
• After that we will initialize an empty list .
• Then we will traverse from start to end and check which year is a leap year . If any year is a leap year then it will be appended to the empty list
• At last the list will be printed .

start=1900
end=2101
years=[]
for year in range(start,end+1):
    if year%400==0:
        years.append(year)
    elif year%4==0 and year%100!=0:
        years.append(year)
print(years)

[1904, 1908, 1912, 1916, 1920, 1924, 1928, 1932, 1936, 1940, 1944, 1948, 1952, 1956, 1960, 1964, 1968, 1972, 1976, 1980, 1984, 1988, 1992, 1996, 2000, 2004, 2008, 2012, 2016, 2020, 2024, 2028, 2032, 2036, 2040, 2044, 2048, 2052, 2056, 2060, 2064, 2068, 2072, 2076, 2080, 2084, 2088, 2092, 2096]

Python program to print all leap years between two given years

Implementing the above code defining a function

def is_leap_year(year):
    if year%400==0:
        return True
    # checking if the year divisible by 4 and not by 100    
    elif year%4==0 and year%100!=0:
        return True    
    else:
        return False
 
def leap_years_in_between_two_years(startYear,endYear):
    years=[]
    for year in range(startYear,endYear+1):
        if is_leap_year(year):
            years.append(year)
    return years

print(leap_years_in_between_two_years(1900,2101))
print(leap_years_in_between_two_years(2000,2010))

[1904, 1908, 1912, 1916, 1920, 1924, 1928, 1932, 1936, 1940, 1944, 1948, 1952, 1956, 1960, 1964, 1968, 1972, 1976, 1980, 1984, 1988, 1992, 1996, 2000, 2004, 2008, 2012, 2016, 2020, 2024, 2028, 2032, 2036, 2040, 2044, 2048, 2052, 2056, 2060, 2064, 2068, 2072, 2076, 2080, 2084, 2088, 2092, 2096]
[2000, 2004, 2008]

Thank you for reading this Article . If You enjoy it Please Share the article . If you want to say something Please Comment .